Calculators/Physics/Adiabatic process

Adiabatic process

p₁V₁^κ = p₂V₂^κ · compression and expansion

Adiabatic process — illustration
Final pressure p₂
263,901.6 Pa
Temperature ratio T₂/T₁
1.3195
Adiabatic compression → the gas heats up (T rises)

In an adiabatic process there is no heat exchange with the surroundings: p·V^κ = const. Compressing the gas does work on it, which raises its temperature (that is why a bicycle pump warms up).

An adiabatic process takes place with no heat exchange with the surroundings (Q = 0) — for example during rapid compression or expansion of a gas. It is governed by the equation:

p1V1κ=p2V2κp_1 V_1^{\kappa}=p_2 V_2^{\kappa}

where κ=cp/cV\kappa=c_p/c_V is the adiabatic index (1.4 for a diatomic gas such as air, 1.67 for a monatomic one). The temperature changes according to T1V1κ−1=T2V2κ−1T_1 V_1^{\kappa-1}=T_2 V_2^{\kappa-1}.

The effect: compressing a gas adiabatically warms it up (the work turns into internal energy — which is why a bicycle pump heats up), and expanding it cools it down (the principle behind refrigerators and the formation of clouds).

Examples

Air (κ=1.4), p₁=100 kPa, V₁=1 m³ → V₂=0.5 m³
→ p₂ = 100·2^1.4 ≈ 264 kPa; T₂/T₁ ≈ 1.32 (it heats up)
Expansion to V₂ = 2·V₁
→ pressure and temperature decrease

Frequently asked questions

Why does a compressed gas heat up?+

Because we do work on it, and with no heat exchange all of that energy raises the internal energy of the gas — that is, its temperature. Hence the warm pump and the hot air in a diesel engine.

How does an adiabat differ from an isotherm?+

On an isotherm the temperature is constant (the gas exchanges heat) and p·V = const. On an adiabat there is no heat, so the temperature changes and p·V^κ = const — the adiabat falls more steeply than the isotherm.

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