Calculators/Physics/Transformer

Transformer

Turns ratio · voltages and currents

Transformer — illustration
Primary winding
Secondary winding
Voltage U₂
57.5
V
Current I₂
8
A
Turns ratio n₁/n₂
4
Step-down transformer · power P ≈ 460 W (ideally conserved)

Ideal transformer: U₁/U₂ = n₁/n₂ = I₂/I₁. Stepping the voltage up lowers the current (and vice versa) — the power P = U·I stays constant (lossless).

A transformer changes the voltage of an alternating current thanks to electromagnetic induction. In an ideal transformer:

U1U2=n1n2=I2I1\frac{U_1}{U_2}=\frac{n_1}{n_2}=\frac{I_2}{I_1}

where n1,n2n_1, n_2 are the numbers of turns of the primary and secondary windings. The ratio n1/n2n_1/n_2 is the turns ratio. When n2>n1n_2>n_1, the transformer steps the voltage up; when n2<n1n_2<n_1 — it steps it down.

Key point: by stepping the voltage up, a transformer steps the current down by the same factor (and vice versa), because the power P=U⋅IP=U\cdot I stays constant (in the ideal, lossless case). This is why energy is transmitted over high-voltage lines — a small current means small losses.

Examples

n₁=1000, n₂=250, U₁=230 V, I₁=2 A
→ U₂ = 57.5 V, I₂ = 8 A (step-down)
n₂ = 4·n₁
→ voltage ×4, current ÷4 (step-up)

Frequently asked questions

Why does a transformer step voltage up and current down?+

Because power is conserved (P = U·I). If the voltage rises 4×, the current must drop 4× so that the product — the power — stays the same.

Why is energy transmitted at high voltage?+

Because line losses are proportional to I²·R. A transformer raises the voltage and lowers the current, so losses shrink — and near the consumer another transformer brings the voltage back down.

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