Formulas & tables/Physics/Gravitation/First cosmic velocity (circular orbital speed)

First cosmic velocity (circular orbital speed)

vI=GMRv_I=\sqrt{\dfrac{GM}{R}}

Result unit: m/s (often given in km/s)

What it describes

The first cosmic velocity is the smallest speed that must be given to a body right at a planet's surface (or that of another celestial body) for it to enter a circular orbit around it — to become a satellite — instead of falling back to the surface.

Symbols

vIv_I
first cosmic velocity
[m/s]
GG
gravitational constant (≈6.67⋅10−11\approx 6.67\cdot10^{-11})
[N·m²/kg²]
MM
mass of the central body (e.g. the planet)
[kg]
RR
orbital radius (at the surface ≈ the planet's radius)
[m]

Where it comes from

In a circular orbit gravity plays the role of the centripetal force. Setting them equal: GMmR2=mv2R\dfrac{GMm}{R^2} = \dfrac{mv^2}{R}. The satellite's mass mm cancels, leaving v2=GMRv^2 = \dfrac{GM}{R}, that is vI=GMRv_I = \sqrt{\dfrac{GM}{R}}. Conclusion: the first cosmic velocity does NOT depend on the satellite's mass.

When to use it

For motion in a circular orbit just above the surface (R≈R \approx the planet's radius). For Earth vI≈7.9v_I \approx 7.9 km/s (≈ 7900 m/s). Equivalently vI=gRv_I = \sqrt{gR}, since g=GMR2g = \dfrac{GM}{R^2}.

Example

Find the first cosmic velocity for Earth.
SubstitutionM=5.97⋅1024M = 5.97\cdot10^{24} kg, R=6.37⋅106R = 6.37\cdot10^{6} m, G=6.67⋅10−11G = 6.67\cdot10^{-11}.
ResultvI=6.67⋅10−11⋅5.97⋅10246.37⋅106≈7.9⋅103v_I = \sqrt{\dfrac{6.67\cdot10^{-11}\cdot 5.97\cdot10^{24}}{6.37\cdot10^{6}}} \approx 7.9\cdot10^{3} m/s ≈ 7.9 km/s.

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