Time dilation

In special relativity, time runs slower for an object moving relative to us: Δt=γ·Δt₀, where the Lorentz factor γ=1/√(1−v²/c²). At low speeds γ≈1 (classical time), but as v approaches c, γ grows without bound. Change the rocket's speed.

Time dilation
Physics · Theory of relativity · Time dilation (FIZ.STW)
Rocket speed vv (as a fraction of cc)0.300 c
A clock in a fast rocket (relative to us) runs…
speed v/c
0.300 c
Lorentz factor γ
1.05
Δt / Δt₀
1.05×
clock rate
0.954×
🎯 Challenge: hit the factor γ
streak: 0

I will give you a target Lorentz factor — tune the rocket speed to reach it. γ = 1/√(1−v²/c²).

What just happened?

The rocket sped up to near the speed of light, and its light clock began to tick slower than ours. This is time dilation — moving clocks run slow.

Time dilation:

γ=11−v2/c2,  Δt=γ Δt0\gamma=\frac{1}{\sqrt{1-v^2/c^2}}, \; \Delta t=\gamma\,\Delta t_0

— Δt0\Delta t_0 is the proper time (measured by the moving clock), and Δt\Delta t is the time in our frame. Since γ≥1\gamma\ge 1, more of it passes for us: the moving clock "falls behind".

When is the effect noticeable?

For everyday speeds v≪cv\ll c, so γ≈1\gamma\approx 1 and the difference is immeasurable — time flows "classically". The effect becomes dramatic only when vv approaches cc (then γ→∞\gamma\to\infty).

The twin paradox:

A twin who flies off in a fast rocket and returns will be younger than the one who stayed on Earth — because less proper time passed in their frame. This is not an illusion, but a real consequence of Δt=γ Δt0\Delta t=\gamma\,\Delta t_0.

Why you need this for the exam:

The formula Δt=γΔt0\Delta t=\gamma\Delta t_0 plus computing γ from v/cv/c solves typical problems on time dilation and the twin paradox. The trick: identify which clock measures the proper time Δt0\Delta t_0 (the one that moves), and multiply by γ.

Remember: moving clocks run slow — Δt = γ·Δt₀. The closer to c, the larger γ; for v≪c γ≈1 and the effect vanishes.

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Theory & formulas

Lorentz factor

In special relativity, a key role is played by the factor: γ=11−v2c2≥1\gamma = \dfrac{1}{\sqrt{1 - \dfrac{v^2}{c^2}}} \ge 1

Time dilation

A clock moving relative to an observer runs slower: Δt=γ Δt0\Delta t = \gamma\,\Delta t_0 where Δt0\Delta t_0 is the proper time (measured in the clock's own frame).

When you can see it

At everyday speeds γ≈1\gamma \approx 1 and the effect is immeasurable. Only when vv is close to cc does the factor γ\gamma grow sharply. Hence the twin paradox: the traveller returns younger.

Notation: γ\gamma — Lorentz factor, vv — speed of the object, c≈3⋅108 m/sc \approx 3\cdot10^8\ \mathrm{m/s}, Δt0\Delta t_0 — proper time, Δt\Delta t — time in the observer's frame.

Frequently asked questions

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What is time dilation?

The slowing of the passage of time measured for an object moving relative to an observer: Δt=γ·Δt₀.

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When is the effect noticeable?

Only at speeds comparable to the speed of light. At everyday speeds γ≈1 and the effect is immeasurable.

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The twin paradox?

A twin who flies off in a fast rocket and returns is younger than the one who stayed — because their clock (proper time) ran slower.

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