Virtual laboratory/Physics/Relativity/Twin paradox — time dilation

Twin paradox — time dilation

Increase the twin's travel speed. Their time runs slower by the Lorentz factor γ=1/√(1−v²/c²), so after the trip they are younger than the twin who stayed on Earth. The closer to c, the larger the age difference.

Twin paradox — time dilation
Physics · Relativity · Twin paradox (FIZ.STW.PR.02)
Travel speed v=βcv = \beta c0.50 c
A twin returning from a trip near the speed of light is:
speed v
0.50 c
factor γ
1.15
traveller age
34.6 yr
difference Δ
5.4 yr
🎯 Challenge: hit the age difference
streak: 0

I’ll give you a target age difference between the twins — tune the speed so the travelling twin comes back younger by exactly that. Δ = t − t/γ, a journey of 40 Earth years.

What just happened?

The twin flew close to the speed of light and came back. Their clock — and with it the heart, the cells, the whole body — ticked slower than on Earth, so they aged less. It is not an illusion: it is real time dilation.

Lorentz factor:

γ=11−v2c2≥1\gamma = \dfrac{1}{\sqrt{1 - \dfrac{v^2}{c^2}}} \ge 1

— for every speed v<cv < c we have γ≥1\gamma \ge 1. β = v/c is the speed as a fraction of the speed of light, c ≈ 3·10⁸ m/s.

The traveller’s proper time:

t′=tγΔ=t−tγt' = \dfrac{t}{\gamma} \qquad \Delta = t - \dfrac{t}{\gamma}

t — time measured on Earth, t′ — time experienced by the traveller. Since γ≥1\gamma \ge 1, then t′≤tt' \le t — the traveller always comes back younger.

Why isn’t it symmetric?

The “paradox” disappears because the twins are not equivalent: it is the rocket that brakes and turns around — it accelerates. Only the traveller changes reference frame, so it is their time that runs shorter. The Earth twin stays in a single inertial frame the whole time.

Why you need this for the exam:

γ = 1/√(1−β²) and t′ = t/γ solve problems on time dilation and length contraction. The trick: compute γ from the speed, then simply divide (time) or multiply — and remember that γ is never less than 1.

Remember: the closer to the speed of light, the larger γ and the slower the traveller’s time runs — they come back younger. t′ = t/γ, and γ ≥ 1 always.

Illustrative model · NexTutor Virtual laboratory

Enjoyed the experiment? Share it.

It's free — send it to friends from school.

Theory & formulas

Time dilation

The clock of a twin travelling at speed vv runs slower by the Lorentz factor: Δt=γ Δt0,γ=11−v2c2≥1\Delta t = \gamma\,\Delta t_0,\qquad \gamma = \dfrac{1}{\sqrt{1 - \dfrac{v^2}{c^2}}} \ge 1

Who is younger

After the trip the travelling twin has aged less than the twin who stayed on Earth — their proper time Δt0\Delta t_0 was shorter. The closer to cc, the larger the age difference.

Why it is not symmetric

The situation is not symmetric, because it is the travelling twin who turns around — changing reference frame (accelerating). This breaks the symmetry and decides which twin actually gets "younger".

Notation: γ\gamma — Lorentz factor, vv — the traveller's speed, cc — the speed of light, Δt0\Delta t_0 — the traveller's proper time, Δt\Delta t — time on Earth.

Frequently asked questions

›

Which twin is younger?

The one who travelled at a speed close to c — their proper time ran slower (time dilation), so they aged less.

›

Why is it not symmetric?

Because the travelling twin turns around — changing reference frame (accelerating), which breaks the symmetry, so it is that twin who actually gets "younger".

›

What is the Lorentz factor?

γ=1/√(1−v²/c²)≥1; it tells how many times slower time runs and more strongly lengths contract at speed v.

Teaching? Embed this experiment on your site.

Free widget — paste it on your school site, blog or notes. It links to the full version.

Teaching a class or tutoring? Guide students in NexTutor →