Virtual laboratory/Mathematics/Calculus/Gabriel's horn — finite volume, infinite surface area

Gabriel's horn — finite volume, infinite surface area

An extension of the topic of solids of revolution and integrals (a curiosity). The solid formed by rotating y=1/x has a finite volume (π) but an infinite surface area — a paradox: "you can fill it with paint, but you cannot coat it". The volume (the integral of 1/x²) converges, the surface area (the integral of 1/x) diverges. It was discovered by Evangelista Torricelli in 1643.

Gabriel's horn — finite volume, infinite surface area
Mathematics · Calculus · Gabriel’s horn — finite volume, infinite surface area (1643)
Solid length (xx: 1 → L)L = 10
Can a solid with a finite volume have an infinite surface area?
length L
10
volume V
2.8274
limit π
3.1416
surface S
14.468
surface →
∞
🎯 Challenge: finite or infinite?
streak: 0

I’ll give you a quantity related to Gabriel’s horn — decide whether it is finite or infinite. Trick: ∫1/x² converges, ∫1/x diverges.

What just happened?

By rotating the curve y=1/xy = 1/x (for x≥1x \ge 1) about the X axis, you get an infinitely long horn — Gabriel’s horn. Astonishingly: although the solid is infinitely long, its volume is finite and equals exactly π\pi, yet its surface area is infinite.

Volume — a convergent integral:

V=π∫1∞1x2 dx=π[−1x]1∞=πV = \pi\int_1^\infty \frac{1}{x^2}\,dx = \pi\Big[-\tfrac1x\Big]_1^\infty = \pi

The integral ∫1∞1/x2 dx\int_1^\infty 1/x^2\,dx is convergent — the volume tends to the finite value π≈3.14\pi \approx 3.14.

Surface area — a divergent integral:

S∼2π∫1∞1x dx=∞S \sim 2\pi\int_1^\infty \frac{1}{x}\,dx = \infty

The integral ∫1∞1/x dx\int_1^\infty 1/x\,dx is divergent (it grows like ln⁡x\ln x, exactly like the harmonic series) — the surface area has no limit at all.

The painter’s paradox:

Hence the famous question: you can fill the horn with a finite amount of paint (volume π\pi), but the same paint would not be enough to paint its infinite inner surface. The resolution: “filling” and “painting” are different notions (volume vs area), and the paint layer has a thickness that also tends to zero as the horn narrows.

Torricelli’s discovery (1643):

The paradox was discovered by Evangelista Torricelli — even before the full development of differential calculus! He was astonished by his own result. It is a classic example of the difference between a convergent and a divergent integral and of how infinity breaks physical intuition.

Why you need this for the exam:

Gabriel’s horn is a flagship example of solids of revolution and improper integrals. Trick: you compute both quantities for the same solid, but check separately whether each integral converges. ∫1/x2\int 1/x^2 converges, ∫1/x\int 1/x diverges — which is why a finite volume and an infinite surface area coexist.

Remember: Gabriel’s horn has a finite volume π\pi and an infinite surface area — because ∫1∞1/x2\int_1^\infty 1/x^2 converges while ∫1∞1/x\int_1^\infty 1/x diverges. A finite volume does not guarantee a finite surface area.

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Theory & formulas

Solid of revolution

We rotate the graph of y=1xy=\tfrac1x for x≥1x\ge 1 about the OXOX axis.

Volume (finite)

V=π∫1∞1x2 dx=πV=\pi\int_1^{\infty}\frac{1}{x^2}\,dx=\pi

Surface area (infinite)

S=2π∫1∞1x1+1x4 dx ≥ 2π∫1∞dxx=∞S=2\pi\int_1^{\infty}\frac{1}{x}\sqrt{1+\tfrac{1}{x^4}}\,dx\ \ge\ 2\pi\int_1^{\infty}\frac{dx}{x}=\infty The integral of 1x2\tfrac1{x^2} is convergent, while the integral of 1x\tfrac1x is divergent (like the harmonic series). Hence the paradox: finite volume, infinite surface area.

Notation: VV the volume, SS the surface area, xx the variable of integration.

Frequently asked questions

›

Can a solid with a finite volume have an infinite surface area?

Yes — Gabriel's horn has volume π (finite), but an infinite surface area.

›

Why is the volume finite but the surface area not?

Because the volume integral (1/x²) is convergent, while the surface integral (1/x) is divergent, like the harmonic series.

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What is the painter's paradox?

You can fill the horn with a finite amount of paint (volume π), but it is not enough to coat its infinite surface.

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