Virtual laboratory/Physics/Atomic physics/The Franck–Hertz experiment — quantised energy levels

The Franck–Hertz experiment — quantised energy levels

An extension of the topic of energy levels and the atomic model. In a tube filled with mercury vapour the electron current rises with voltage, but drops sharply at specific, evenly spaced values — the electrons hand the atoms exactly quantised portions of energy. Proof that the atom's energy levels are quantised (Franck and Hertz, Nobel Prize 1925).

The Franck–Hertz experiment — quantised energy levels
Physics · Atomic physics · Franck–Hertz experiment (FIZ.ATOM.PR.02)
Accelerating voltage UU3.0 V
Current dips at specific voltages prove that the atom's energy is…
voltage U
3.0 V
current I
3.00 µA
excitations
0×
excitation energy
4.9 eV
🎯 Challenge: count the excitations
streak: 0

I will give you a voltage U — guess how many times the electron collides inelastically (how many excitations) before it reaches the anode. Threshold E_exc = 4.9 V.

What just happened?

Electrons accelerated by the voltage U strike mercury atoms. As long as their energy is below 4.9 eV, the collisions are elastic — the current rises with U. Once their energy reaches 4.9 eV, the electron collides inelastically: it hands the atom exactly that portion and almost stops itself — the anode current drops sharply.

The quantised portion of energy:

ΔE=e ΔU≈4.9 eV\Delta E = e\,\Delta U \approx 4{.}9\ \text{eV}

— the atom accepts energy only in a precisely defined "packet". e — the electron charge, ΔU — the voltage spacing between dips, ΔE — the atom's excitation energy.

Why are the dips evenly spaced?

At higher U the electron has time to excite an atom once more — hence the second, third and fourth "packet" of losses. The spacing between dips is constant, because it is still the same portion of energy:

Un≈n⋅ΔEeΔU=constU_n \approx n\cdot\dfrac{\Delta E}{e} \qquad \Delta U = \text{const}

What did this prove?

If the atom's energy were continuous, the current would rise smoothly. The evenly spaced, repeating dips prove that the atom has quantised energy levels — a direct confirmation of the Bohr model.

Why this matters for the exam:

It is the flagship proof of energy quantisation in the atom. Trick: equal spacing of the dips = one quantised portion ΔE = e·ΔU. From the voltage spacing you can calculate the atom's excitation energy.

Remember: evenly spaced current dips in the Franck–Hertz tube are the signature of the atom's quantised levels — energy is accepted only in portions ΔE = e·ΔU.

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Theory & formulas

Quantised levels

In a tube filled with mercury vapour the electron current rises with voltage, but drops sharply at evenly spaced values (every ~4.9 V for mercury).

Why

Electrons lose energy in inelastic collisions, handing the atoms exactly a quantised portion — the excitation energy: eU=ΔEeU = \Delta E Equal spacing of the dips = a fixed portion of energy. Proof of the quantisation of the atom's energy levels (Nobel Prize 1925).

Notation: ee — the elementary charge, UU — the accelerating voltage, ΔE\Delta E — the atom's excitation energy.

Frequently asked questions

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What did the Franck–Hertz experiment prove?

That the atom's energy is quantised — the atom accepts energy only in specific portions.

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Why does the current drop at specific voltages?

Because the electrons reach the atom's excitation energy and lose it in inelastic collisions.

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What do the evenly spaced dips mean?

That the portion of energy (the quantum) is fixed — successive dips roughly every 4.9 V for mercury.

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