Virtual laboratory/Physics/Magnetism/Lorentz force — a charge moving in a magnetic field

Lorentz force — a charge moving in a magnetic field

A charge moving in a magnetic field feels the Lorentz force F=qvB·sinα, always perpendicular to the velocity. That is why a charge entering perpendicular to field B moves along a circle of radius r=mv/(qB). The Lorentz force does no work — it changes only the direction, not the magnitude of the velocity. Change v, B and q.

Lorentz force — a charge moving in a magnetic field
Physics · Magnetism · Lorentz force (FIZ.MAG)
Velocity vv3.0 Mm/s
Flux density BB0.8 T
Charge qq1 e
A charge enters perpendicular to field B. It moves along a…
velocity v
3.0 Mm/s
flux density B
0.8 T
force F=qvB
3.84·10⁻¹³N
radius r
3.75 cm
🎯 Challenge: hit the force
streak: 0

I'll give you a target Lorentz force — tune velocity, flux density and charge to reach it. F = qvB.

What just happened?

The charge flew in perpendicular to the magnetic field and, instead of going straight, curved into a circle. It keeps turning the same way and returns to its starting point.

The Lorentz force:

F=qvBsin⁡αF = qvB\sin\alpha

— the force acting on a charge moving in a magnetic field. It is perpendicular both to the velocity vv and to the field BB. For perpendicular entry α=90∘\alpha = 90^\circ, so F=qvBF = qvB.

Why is the path circular?

The force has a constant magnitude and always points toward the centre — a perfect centripetal force. Setting it equal to mv2/rmv^2/r:

qvB=mv2r  ⇒  r=mvqBqvB = \dfrac{mv^2}{r} \;\Rightarrow\; r = \dfrac{mv}{qB}

A stronger field BB or a larger charge qq → a tighter circle. A higher velocity vv → a wider circle.

Why does the speed not change?

The force is perpendicular to the velocity, so it does no work — it neither speeds up nor slows the charge. Only the direction of motion changes, while the speed ∣v∣|v| stays constant.

Where does this apply?

The cyclotron (accelerates particles along a spiral), the aurora (charged solar-wind particles enter Earth's field), the old cathode-ray tube (deflecting the electron beam).

Why you need this for the exam:

Two formulas — F=qvBF = qvB and r=mv/(qB)r = mv/(qB) — solve most problems about a charge moving in a magnetic field. The trick: the Lorentz force is centripetal, so compare qvB=mv2/rqvB = mv^2/r and solve for the unknown quantity.

Remember: a charge entering perpendicular to field B circles with radius r=mv/(qB)r = mv/(qB), and its speed does not change — the Lorentz force only turns it.

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Theory & formulas

The Lorentz force

A charge moving in a magnetic field feels the force: F=q v B sin⁡αF = q\,v\,B\,\sin\alpha It is always perpendicular to the velocity and to the field. For motion perpendicular to BB (α=90∘\alpha=90^\circ) its magnitude is F=qvBF = qvB.

Circular motion

Being perpendicular to the velocity, the force acts as the centripetal force (qvB=mv2rqvB = \tfrac{mv^2}{r}), so the charge circles with radius: r=mvqBr = \dfrac{m v}{q B}

No work

The Lorentz force is perpendicular to the displacement, so it does no work — it changes the direction, not the magnitude of the velocity. Applications: cyclotrons, the aurora, mass spectrometers.

Symbols: FF — Lorentz force, qq — charge, vv — velocity, BB — magnetic flux density, α\alpha — angle between vv and BB, mm — mass, rr — radius of the circle.

Frequently asked questions

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What is the Lorentz force?

The force F=qvB·sinα acting on a charge moving in a magnetic field, perpendicular to the velocity and to the field.

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Why is the path circular?

Because the Lorentz force stays perpendicular to the velocity and acts as the centripetal force (qvB=mv²/r), bending the path into a circle.

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Where does this apply?

In cyclotrons and accelerators, in the formation of the aurora, in cathode-ray tubes and mass spectrometers.

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