Virtual laboratory/Physics/Nuclear physics/Nuclear radiation — penetration and shielding

Nuclear radiation — penetration and shielding

Pick the type of radiation and a shield. α radiation is stopped by a sheet of paper, β by an aluminium plate, and penetrating γ only by a thick layer of lead. The dose also decreases with distance (∝1/d²). Check what gets through the barrier.

Nuclear radiation — penetration and shielding
Physics · Nuclear physics · Penetration and doses (FIZ.JADRO.PP.05)
Type of radiation
Shield
Distance from source dd2.0 u.
The best shield against γ radiation is…
type
α
shield
paper
distance d
2.0 u.
rel. dose
0.0 %
🎯 Challenge: hit the relative dose
streak: 0

I will give you a target dose behind the shield — pick the type of radiation, the shield and the distance d to reach it. D = T·1/d².

What just happened?

The same shield stops different radiation to different degrees. α particles are heavy and charged — a sheet of paper already stops them. β electrons are stopped by a few millimetres of aluminium. γ photons have no charge and penetrate the deepest — only thick lead attenuates them significantly.

Penetration increases in the order:

α<β<γ\alpha < \beta < \gamma

α — helium nuclei (paper), β — electrons (aluminium), γ — photons (thick lead). The smaller the charge and mass, the greater the range in matter.

Dose vs. distance:

Radiation from a point source spreads over an ever-larger sphere, so the intensity (and with it the dose) falls off with the square of the distance:

I∼1d2⇒D=T⋅1d2I \sim \dfrac{1}{d^{2}} \qquad \Rightarrow \qquad D = T\cdot\dfrac{1}{d^{2}}

Moving 2× farther reduces the dose 4×; moving 3× farther — as much as 9×. That is why distance is one of the simplest and cheapest methods of protection (alongside time and shielding).

Why you need this for the exam:

Nuclear problems like to ask "what to shield with" and "how many times weaker the dose is after moving away". Trick: memorise the order of shields (paper → aluminium → lead) and the 1/d21/d^2 rule — the rest is just plugging in numbers.

Remember: a sheet of paper stops α, aluminium stops β, and only thick lead stops γ; and the dose falls off with the square of the distance (1/d21/d^2).

Illustrative model · NexTutor Virtual laboratory

Enjoyed the experiment? Share it.

It's free — send it to friends from school.

Theory & formulas

Penetration vs. shielding

The ability to penetrate matter increases in the order α<β<γ\alpha < \beta < \gamma:

  • α\alpha — stopped by a sheet of paper or the skin,
  • β\beta — stopped by an aluminium plate,
  • γ\gamma — requires a thick layer of lead or concrete.

Attenuation in a material

The intensity of γ\gamma radiation decreases exponentially with the thickness of the shield xx: I=I0 e−μxI = I_0\,e^{-\mu x}

Effect of distance

The dose from a point source decreases with the square of the distance: I∼1d2I \sim \dfrac{1}{d^2} Moving twice as far away reduces the dose fourfold.

Notation: II — intensity after passing through the shield, I0I_0 — initial intensity, μ\mu — attenuation coefficient of the material, xx — shield thickness, dd — distance from the source.

Frequently asked questions

›

What shields best against γ radiation?

A thick layer of high-density material, e.g. lead or concrete — γ is the most penetrating.

›

Which radiation is the least penetrating?

Alpha (α) — it is stopped by a sheet of paper or the skin, but it is dangerous once it enters the body.

›

How does distance affect the dose?

The intensity decreases with the square of the distance (∝1/d²), so moving away effectively reduces the dose.

Teaching? Embed this experiment on your site.

Free widget — paste it on your school site, blog or notes. It links to the full version.

Teaching a class or tutoring? Guide students in NexTutor →