Virtual laboratory/Physics/Atomic physics/Radioactive decay — half-life and the formula N = N₀(½)^(t/T)

Radioactive decay — half-life and the formula N = N₀(½)^(t/T)

What we'll do: We'll track how many radioactive nuclei remain in a sample as successive half-lives pass.

What you see on screen: A sample of nuclei as a grid of glowing dots that fade out as they decay, isotope presets (C-14, I-131, Ra-226) and a time slider. Beside it, the N(t) curve with markers after each half-life (100→50→25%). Readouts: the half-life T, time, the number of remaining and decayed nuclei, and the percentage remaining.

Radioactive decay — half-life and the formula N = N₀(½)^(t/T)
Physics · Atomic physics · Radioactive decay (FIZ.JADRO.PP.05)
Time (in half-lives)t = 0.0·T = 0 years
After 2 half-lives, the fraction of the sample remaining will be:
isotope
C-14
half-life T
5,730 years
time t (0.0 T)
0 years
remaining N
1,000
decayed
0
% remaining
100.0%
🎯 Challenge: hit the % remaining
streak: 0

I'll give you a target percentage of nuclei remaining — set the time with the slider to reach it. N = N₀·(½)^(t/T).

What just happened?

After one half-life 50% of the nuclei remain, after the second 25%, after the third 12.5% — each time half of the previous amount. It never reaches zero.

What is a half-life?

It is the time T after which half of the radioactive nuclei in a sample decay. It is a fixed property of the isotope — it does not depend on temperature, pressure, or how many nuclei there were at the start.

The decay law:

N=N0(12)t/TN = N_0 \left(\tfrac{1}{2}\right)^{t/T}

N₀ — the number of nuclei at the start, N — after time t. The same formula works for the mass of the sample and for the activity.

Why exponential, not linear?

Because in each half-life HALF of what IS LEFT decays — not a fixed portion. The fewer nuclei, the fewer decays, so the curve falls more and more slowly and in theory never reaches zero.

Dating:

knowing the half-life T of carbon C-14 (5730 years) and measuring how much is left, the age of remains is calculated.

Why you need this for the exam:

the formula N=N0(12)t/TN = N_0(\tfrac{1}{2})^{t/T} and working out “how many half-lives” are the core of nuclear physics problems. The trick: compute t/T, then raise ½ to that power.

Remember: after each half-life, half of the previous amount remains — decay is exponential, and the half-life T does not depend on external conditions.

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Theory & formulas

The decay law

N=N0(12)t/TN = N_0\left(\tfrac12\right)^{t/T} After each half-life TT one half of the nuclei remains: 100% → 50% → 25% → 12.5%…

Exponential form

N=N0 e−λt,λ=ln⁡2TN = N_0\,e^{-\lambda t}, \qquad \lambda = \dfrac{\ln 2}{T} TT is constant for a given isotope (e.g. C-14 ~5700 years — dating; I-131, Ra-226).

Notation: NN — the number of nuclei after time tt, N0N_0 — the initial number, TT — the half-life, λ\lambda — the decay constant, tt — time.

Frequently asked questions

›

What is a half-life?

The time after which half of the radioactive nuclei in a sample decay; it is constant for a given isotope.

›

What is the law of radioactive decay?

N = N₀·(½)^(t/T), where t is time and T is the half-life.

›

How much of a sample remains after three half-lives?

One eighth (12.5%) — after each half-life, half of the previous amount remains.

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