Moment of inertia

The moment of inertia I is a measure of a body's resistance to changes in rotational motion — it depends on the mass distribution: hoop I=mR², cylinder ½mR², sphere ⅖mR². When rolling down a ramp the potential energy splits between translational and rotational motion; the sphere rolls down fastest, because it has the smallest I relative to its mass. Pick a body shape.

Moment of inertia
Physics · Rigid body · Moment of inertia (FIZ.BRYL)
Body shape
I=25mR2I = \tfrac25 mR^2
Mass mm1.0 kg
Radius RR0.20 m
Which rolls down the ramp faster (same mass and radius)?
mass m
1.0 kg
radius R
0.20 m
moment I
0.016
speed v
4.10 m/s
🎯 Challenge: which body wins the ramp race?

What just happened?

From the same ramp the sphere rolled down faster than the hoop. Both convert the same potential energy mghmgh, but the hoop must "hide" a larger part of it in rotational motion — so less is left for speeding up downhill.

What is moment of inertia?

It is a measure of a body’s resistance to changes in rotational motion — the rotational counterpart of mass. It depends not only on the mass, but also on its distribution about the axis: the farther the mass is from the axis, the larger II. For uniform bodies I=c mR2I = c\,mR^2.

Ihoop=mR2,Icyl=12mR2,Isphere=25mR2I_{\text{hoop}}=mR^2,\quad I_{\text{cyl}}=\tfrac12 mR^2,\quad I_{\text{sphere}}=\tfrac25 mR^2

The hoop has all its mass on the rim (far from the axis) → the largest c=1c=1. The sphere also has mass spread near the center → the smallest c=25c=\tfrac25.

Energy balance when rolling:

mgh=12mv2+12Iω2,ω=vRmgh = \tfrac12 m v^2 + \tfrac12 I\omega^2,\qquad \omega=\dfrac{v}{R}

Rotational energy Erot=12Iω2E_{rot}=\tfrac12 I\omega^2. Substituting I=c mR2I=c\,mR^2 and ω=v/R\omega=v/R we get:

v=2gh1+cv=\sqrt{\dfrac{2gh}{1+c}}

Mass and radius cancelled out — the speed at the bottom depends only on the shape cc. A smaller cc ⇒ a larger vv. That is why the order is always: sphere, then cylinder, and the hoop last.

Why you need this for the exam:

You solve rolling problems with a single equation mgh=12mv2+12Iω2mgh=\tfrac12 mv^2+\tfrac12 I\omega^2 with the substitution ω=v/R\omega=v/R. Trick: write out I=c mR2I=c\,mR^2 for the given body, and mm and RR will cancel out by themselves.

Remember: moment of inertia is the resistance to spinning and depends on mass distribution — the farther the mass from the axis, the larger II and the slower the body rolls down.

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Theory & formulas

Moment of inertia

II is a measure of a body's resistance to changes in rotational motion — it depends on the mass distribution about the axis:

  • hoop: I=mR2I = mR^2
  • solid cylinder: I=12mR2I = \tfrac12 mR^2
  • solid sphere: I=25mR2I = \tfrac25 mR^2

Rolling down a ramp

The potential energy splits between translational and rotational motion. Acceleration for rolling without slipping: a=gsin⁡α1+ImR2a = \dfrac{g\sin\alpha}{1 + \dfrac{I}{mR^2}} The smaller I/mR2I/mR^2, the faster — that is why the sphere wins against the cylinder and the hoop.

Notation: II — moment of inertia, mm — mass, RR — radius, α\alpha — ramp angle, gg — gravitational acceleration, aa — linear acceleration.

Frequently asked questions

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What is moment of inertia?

A measure of a body's inertia in rotational motion — it depends on the mass and how it is distributed about the axis. The farther the mass is from the axis, the larger I.

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Why does the sphere roll down faster?

Because it has the smallest I relative to its mass — less energy goes into rotational motion and more into translational, so it speeds up the fastest.

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What does I depend on?

On the body's mass, its shape and how the mass is distributed about the axis of rotation (I = c·mR², where c depends on the shape).

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