Virtual laboratory/Mathematics/Calculus/The golden ratio and the Fibonacci sequence

The golden ratio and the Fibonacci sequence

An extension of the topic of number sequences. The Fibonacci sequence is one of the best-known examples of a recursive sequence: F(n)=F(n-1)+F(n-2). The ratio of consecutive terms F(n)/F(n-1) oscillates, but converges to the golden ratio φ=(1+√5)/2≈1.618 — a constant that also appears in geometry and in nature. Fibonacci introduced the sequence to Europe in his work "Liber Abaci" (1202) — a landmark discovery.

The golden ratio and the Fibonacci sequence
Mathematics · Calculus · The golden ratio and the Fibonacci sequence (1202)
Term index nn8
The ratio of consecutive Fibonacci terms F(n)/F(n-1) tends to…
n
8
F(n)
21
F(n)/F(n-1)
1.6154
|distance from φ|
0.0026
🎯 Challenge: hit the ratio
streak: 0

I will give you a target ratio — choose the term index n so that F(n)/F(n-1) equals it. For small n the ratio jumps around φ.

What just happened?

You moved the slider to a high term index of the Fibonacci sequence. You saw the ratio of consecutive terms stop wavering and settle very close to one specific irrational number — the golden ratio φ.

The Fibonacci sequence:

F(1)=F(2)=1,F(n)=F(n−1)+F(n−2)F(1) = F(2) = 1, \qquad F(n) = F(n-1) + F(n-2)

Each term is the sum of the two preceding ones: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144… The Italian mathematician Leonardo of Pisa, known as Fibonacci, introduced the sequence to Europe in his work “Liber Abaci” (1202), while solving a problem about breeding rabbits — though the sequence itself had already been known to Indian mathematicians.

The golden ratio φ:

φ=1+52≈1.618\varphi = \dfrac{1+\sqrt{5}}{2} \approx 1.618

What is surprising is that a simple recursive sequence of integers leads, “all by itself,” to an irrational number that appears in entirely different areas: in geometry (the golden section of a segment), in art (proportions in architecture and painting) and in nature (the arrangement of sunflower seeds, snail shells, plant branching, spirals in flowers).

Why does the ratio oscillate rather than “hit” φ at once?

For small n the terms are still “immature” and the ratio is now above, now below φ (e.g. 1/1=1, 2/1=2, 3/2=1.5, 5/3≈1.667…). As n grows the difference ∣F(n)/F(n−1)−φ∣|F(n)/F(n-1) - \varphi| steadily decreases — this is exactly the invariant you observe on the chart to the right of the scene.

Why this matters for the exam:

The Fibonacci sequence is a classic example of a recursively defined sequence — a problem type that appears in the chapter on sequences. Remember the definition F(n) = F(n-1) + F(n-2), and that the limit of the ratio of consecutive terms is the golden ratio φ.

Remember: F(n) = F(n-1) + F(n-2), and the ratio F(n)/F(n-1) tends to φ = (1+√5)/2 ≈ 1.618 — the golden ratio present in mathematics, art and nature.

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Theory & formulas

The Fibonacci sequence

F1=F2=1,Fn=Fn−1+Fn−2F_1=F_2=1,\qquad F_n=F_{n-1}+F_{n-2} The successive terms: 1,1,2,3,5,8,13,21,…1,1,2,3,5,8,13,21,\dots

Limit of the ratio

lim⁡n→∞FnFn−1=φ=1+52≈1.618\lim_{n\to\infty}\frac{F_n}{F_{n-1}}=\varphi=\frac{1+\sqrt5}{2}\approx 1.618

A property of the golden ratio

φ\varphi satisfies φ2=φ+1\varphi^2=\varphi+1, that is φ=1+1φ\varphi=1+\dfrac{1}{\varphi} — and this is the source of the convergence of the ratios of consecutive terms.

Notation: FnF_n is the nn-th Fibonacci term, φ\varphi is the golden ratio.

Frequently asked questions

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How is the Fibonacci sequence defined?

Recursively: F(n)=F(n-1)+F(n-2), with F(1)=F(2)=1.

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What does the ratio of consecutive Fibonacci terms tend to?

To the golden ratio φ=(1+√5)/2≈1.618.

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Where else does the golden ratio φ appear?

In geometry (the golden section), in art and in nature (e.g. the arrangement of sunflower seeds, snail shells).

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