Virtual laboratory/Physics/Atomic physics/The Davisson–Germer experiment — matter waves

The Davisson–Germer experiment — matter waves

An extension of the de Broglie wave topic. A beam of electrons strikes a crystal and produces a diffraction pattern — just as waves do (λ=h/p). This is direct confirmation that particles have a wave nature (Nobel Prize 1937).

The Davisson–Germer experiment — matter waves
Physics · Atomic physics · The Davisson–Germer experiment (FIZ.ATOM.PR.05)
Accelerating voltage UU54 V
Lattice spacing dd0.20 nm
An electron beam hits the crystal — on the detector you will see:
voltage U
54 V
momentum p
3.97·10⁻²⁴
wavelength λ
0.167 nm
maximum angle θ₁
57°
🎯 Challenge: hit the maximum angle
streak: 0

I will give you a target angle for the first maximum θ₁ — tune the voltage U and the lattice spacing d so the maximum falls at that angle. d·sinθ = λ = h/p.

What just happened?

The electron beam reflected off the nickel crystal gave not a single spot but a set of maxima — exactly like a wave diffracting off a grating. Davisson and Germer (1927) thereby confirmed de Broglie's matter-wave hypothesis.

The de Broglie matter wave:

λ=hp=h2meU\lambda = \dfrac{h}{p} = \dfrac{h}{\sqrt{2m e U}}

— every particle of momentum pp corresponds to a wave of wavelength λ\lambda. The greater the momentum (the higher the beam energy), the shorter the wave. hh — the Planck constant.

Condition for maxima (Bragg):

d sin⁡θ=n λd\,\sin\theta = n\,\lambda

Maxima arise where the waves scattered off successive lattice planes reinforce one another (the path difference is a whole multiple of λ\lambda). Changing λ\lambda shifts the maxima; hence their position depends on the electrons' momentum.

What does this mean in practice?

An electron is not “just a tiny ball” — it has a wave nature. Electron diffraction is no curiosity: this is how the electron microscope works, as do the diffractometers that probe crystal structure.

Why you need this for the exam:

λ = h/p together with d·sinθ = nλ solves problems on matter waves and diffraction. The trick: compute λ from the momentum (or voltage), then plug it into the Bragg condition to find the maximum angle.

Remember: electrons are matter waves — λ = h/p, and on a crystal they produce a diffraction pattern. This is proof of wave–particle duality.

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Theory & formulas

Electron diffraction

A beam of electrons strikes a crystal and produces a diffraction pattern — just as waves do. This is direct confirmation of de Broglie waves (Nobel Prize 1937).

The Bragg condition

Maxima appear when: 2dsin⁡θ=nλ,λ=hp2d\sin\theta = n\lambda, \qquad \lambda = \dfrac{h}{p} The regular crystal lattice acts as a diffraction grating for the electrons' matter waves.

Symbols: dd — spacing between lattice planes, θ\theta — angle of incidence, nn — order of the maximum, λ\lambda — matter-wave wavelength, hh — Planck constant, pp — electron momentum.

Frequently asked questions

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What did the Davisson–Germer experiment confirm?

The wave nature of electrons — de Broglie's matter-wave hypothesis.

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Why do electrons produce a diffraction pattern?

Because, as waves of wavelength λ=h/p, they diffract off the regular crystal lattice (the Bragg condition).

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What is a matter wave?

A wave description of a particle with wavelength λ=h/p — the greater the momentum, the shorter the wave.

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