Virtual laboratory/Physics/Atomic physics/The de Broglie wave — matter duality

The de Broglie wave — matter duality

Change the particle's momentum. Every particle has a matter wave of wavelength λ=h/p (wave–particle duality); the greater the momentum, the shorter the wave — which is why wave behaviour only shows up for very small particles.

The de Broglie wave — matter duality
Physics · Atomic physics · The de Broglie wave (FIZ.ATOM.PR.05)
Particle momentum pp4.0 a.u.
The greater the particle momentum, the matter wavelength becomes:
momentum p
4.0 a.u.
wavelength λ
3.00 a.u.
product p·λ
12.0
wave number k
2.09
🎯 Challenge: hit the wavelength
streak: 0

I'll give you a target matter wavelength — tune the particle momentum to reach it. λ = h/p.

What just happened?

You doubled the particle momentum, and its matter wave shrank by half. Wavelength and momentum are inversely proportional — that is the heart of wave–particle duality.

The de Broglie hypothesis:

λ=hp\lambda = \dfrac{h}{p}

— every moving particle (an electron, a proton, even a ball) has a matter wave of wavelength λ\lambda. Here hh is the Planck constant, and p=mυp = m\upsilon — the particle momentum.

What does it mean in practice?

The faster and heavier the particle (greater momentum), the shorter its matter wave. That is why wave properties show up for light, slow particles — for macroscopic bodies λ\lambda is vanishingly small and immeasurable. Notice that the product stays constant:

p⋅λ=h=constp\cdot\lambda = h = \text{const}

How do we know?

Electron matter waves are confirmed by diffraction on a crystal (the Davisson–Germer experiment) — electrons, like waves, are diffracted and form an interference pattern. The electron microscope is built on this.

Why you need it for the exam:

The formula λ=h/p\lambda = h/p solves most matter-wave problems. The trick: compute the momentum p=mυp = m\upsilon (or p=2mEkp=\sqrt{2mE_k}), then divide the Planck constant by it. Remember: momentum rises → λ\lambda decreases.

Remember: every particle has a matter wave λ=h/p\lambda = h/p — the wavelength decreases as momentum rises. This is a cornerstone of quantum physics.

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Theory & formulas

Matter wave

Every particle has a wave of wavelength: λ=hp=hmv\lambda = \dfrac{h}{p} = \dfrac{h}{mv} The greater the momentum, the shorter the wave.

Why a ball's wave behaviour is invisible

Macroscopic bodies have enormous momentum, so λ\lambda is unimaginably small — wave behaviour only reveals itself for very small particles (electrons). This is the essence of wave–particle duality.

Notation: λ\lambda — matter wavelength, hh — the Planck constant, p=mvp=mv — momentum, mm — mass, vv — velocity.

Frequently asked questions

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How does momentum affect the matter wavelength?

The opposite — the greater the momentum, the shorter the wave (λ=h/p).

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What is wave–particle duality?

Particles show both particle-like and wave-like features.

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Why is a ball's wave behaviour invisible?

It has enormous momentum — the wavelength is unimaginably small.

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