Virtual laboratory/Physics/Waves and acoustics/Mechanical waves — v = λf

Mechanical waves — v = λf

What we'll do: We'll change the frequency and wavelength (or the medium's speed) and check how the formula v = λf links them.

What you see on screen: A travelling wave with the wavelength marked (between crests) and the oscillation rate, plus sliders for frequency, wavelength and speed; an indicator shows the speed v = λf, and changing the frequency packs the waves closer or spreads them out. Readouts: frequency, wavelength, speed and period.

Mechanical waves — v = λf
Physics · Waves and acoustics · Mechanical waves (FIZ.2.3.3)
Frequency f (source)2,0 Hz
Wave speed v (medium)6,0 m/s
At a constant wave speed you double the frequency. The wavelength:
frequency f
2,0 Hz
wavelength λ
3,00 m
wave speed v
6,0 m/s
period T
0,50 s
🎯 Challenge: hit the wavelength
streak: 0

I'll give you a target wavelength — tune the frequency and speed to reach it. λ = v/f.

What just happened?

Doubling the frequency at a constant wave speed halved the wavelength — the waves “squeezed” closer together.

Three quantities describing a wave:

WAVELENGTH λ — the distance between two successive crests (or troughs); FREQUENCY f — the number of full oscillations per second (in hertz, Hz); WAVE SPEED v — how fast the wave travels through the medium.

They are linked by the formula:

v=λ⋅fv = \lambda \cdot f
λ=vf,T=1f\lambda = \frac{v}{f}, \quad T = \frac{1}{f}

What stays constant?

The wave speed depends on the MEDIUM (e.g. sound in air ~340 m/s), not on the source. That is why, when you raise the frequency, the wavelength decreases — so that the product λ·f (i.e. v) stays the same.

Examples:

a higher pitch means a greater frequency and a shorter wave; in light, a greater frequency corresponds to a different colour.

Why you need this on the exam:

calculations with v=λfv = \lambda f (wavelength, frequency, speed) and understanding what depends on the medium and what on the source are the basis of the waves chapter. Trick: in a constant medium λ and f are inversely proportional.

Remember: v = λ·f; the wave speed depends on the medium, so at its constant value a greater frequency means a shorter wave.

Conceptual model · NexTutor Virtual laboratory

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Theory & formulas

Basic relation

v=λfv = \lambda f The wave speed equals the product of the wavelength and the frequency.

What follows from what

  • the speed vv depends on the medium, not on the source,
  • at a constant vv: a higher frequency → a shorter wave (λ∝1/f\lambda\propto 1/f).

Period

T=1fT = \dfrac{1}{f}

Notation: vv — wave speed, λ\lambda — wavelength, ff — frequency, TT — period.

Frequently asked questions

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What is the relation between wavelength, frequency and wave speed?

v = λ·f — the wave speed equals the product of the wavelength and the frequency.

›

What happens to the wavelength when the frequency increases?

At a constant speed it decreases — the wavelength is inversely proportional to the frequency.

›

What does the wave speed depend on?

On the medium it travels through (e.g. its type and temperature), not on the wave source.

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