Virtual laboratory/Physics/Waves and acoustics/The Doppler effect for sound

The Doppler effect for sound

When a sound source moves, we hear a different frequency than the one emitted: when approaching the waves compress (higher pitch), when receding they spread out (lower pitch) — f′=f·v_sound/(v_sound±v_z). That is why the siren pitch of a passing ambulance falls after it goes by. Change the source speed.

The Doppler effect for sound
Physics · Waves and acoustics · Doppler effect (FIZ.FAL)
Source speed vzv_z (− approaching · + receding)-120 m/s
The ambulance passes you. The siren pitch at the moment it drives past and starts to recede:
speed v_z
-120 m/s
direction
approaching
source f
700 Hz
received f'
1082 Hz
🎯 Challenge: hit the heard frequency
streak: 0

I'll give you a frequency the observer should hear — tune the source speed v_z to reach it. source f = 700 Hz.

Why does the siren change pitch?

The source moves relative to the air and "catches up" to its own waves. In front, the wavefronts compress (shorter wavelength → higher frequency), behind they spread out (longer wavelength → lower frequency). That is why an approaching ambulance sounds higher and a receding one lower.

Doppler effect for sound:

f′=f⋅vsoundvsound±vzf' = f\cdot\frac{v_{sound}}{v_{sound}\pm v_z}

f — source frequency, vsound = 340 m/s — speed of sound, vz — source speed relative to the air. Approaching → smaller denominator → f′>ff' > f; receding → larger denominator → f′<ff' < f.

When does the pitch rise?

When the source and observer approach each other — the received frequency is higher than the source frequency. The largest difference occurs just before passing; right after it the relative velocity changes sign and the pitch drops sharply.

How does it differ from the Doppler effect for light?

Sound needs a medium (air), so its effect depends on motion relative to the medium — frequency changes differently for a moving source than for a moving observer. Light propagates in vacuum with no privileged medium: only the relative velocity matters, and the formula is relativistic (the red/blue shift of the spectrum).

Why you need this for the exam:

Acoustics problems most often ask whether the received frequency rises or falls, and have you substitute into f′=f vsound/(vsound±vz)f' = f\,v_{sound}/(v_{sound}\pm v_z). The trick: determine the direction of relative motion, pick the sign in the denominator, compute.

Remember: approaching → higher pitch, receding → lower pitch, no relative motion → f' = f. That is the essence of the Doppler effect.

Illustrative model · NexTutor Virtual laboratory

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Theory & formulas

Moving source

When a sound source moves, the waves compress in front (higher pitch) and spread out behind (lower pitch): f′=f vsoundvsound±vzf' = f\,\dfrac{v_{sound}}{v_{sound} \pm v_z} the "−" sign for approaching (f′f' rises), "+" for receding (f′f' falls).

The ambulance

That is why the siren pitch of a passing ambulance falls at the moment of passing. Unlike light, sound needs a medium, and the formula depends separately on the motion of the source and the observer.

Notation: f′f' — received frequency, ff — emitted, vsoundv_{sound} — speed of sound, vzv_z — source speed.

Frequently asked questions

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Why does the siren change pitch?

Because the motion of the source compresses the waves ahead of it (higher frequency) and spreads them out behind it (lower) — that is the Doppler effect.

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How does it differ from the Doppler effect for light?

Sound needs a medium and the formula depends separately on the motion of the source and the observer relative to the air; for light only the relative velocity matters.

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When does the pitch rise?

When the source and observer approach each other — the received frequency is then higher than the emitted one.

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