Virtual laboratory/Physics/Electricity/Series and parallel circuits — equivalent resistance

Series and parallel circuits — equivalent resistance

What we'll do: We'll connect two resistors once in series and once in parallel and check how the equivalent resistance changes, and what happens when we unscrew one bulb.

What you see on screen: A circuit diagram with a battery, two resistors and bulbs, a switch for the connection type, and a button to unscrew a bulb. Flowing electrons and bulb brightness show the current; a bar computes the equivalent resistance. Readouts: connection type, resistances, equivalent resistance, current and the branch distribution.

Series and parallel circuits — equivalent resistance
Physics · Electricity · Series and parallel circuits (FIZ.PRAD.PR.13)
Resistance R1R_1 (bulb 1)10 Ω
Resistance R2R_2 (bulb 2)10 Ω
In a parallel circuit you unscrew one bulb — the other one:
connection
Parallel
R₁
10 Ω
R₂
10 Ω
equiv. resistance Rz
5.0 Ω
total current I
1.200 A
Branches (parallel): shared voltage U = 6 V · current splits: I₁ = 0.600 A, I₂ = 0.600 A
🎯 Challenge: hit the equivalent resistance
streak: 0

I'll give you a target equivalent resistance — choose the connection (series/parallel) and R₁ and R₂ to reach it.

What just happened?

In a parallel circuit unscrewing one bulb did not put out the other — because each has its own independent path for the current.

Series connection:

resistors one after another, a single path for the current. The equivalent resistance ADDS UP:

Rz=R1+R2R_z = R_1 + R_2

The current is the same everywhere, but any break puts out the whole circuit (because it breaks the only path).

Parallel connection:

resistors side by side, each on its own branch. The equivalent resistance is computed from reciprocals:

1Rz=1R1+1R2\dfrac{1}{R_z} = \dfrac{1}{R_1} + \dfrac{1}{R_2}

Each branch has the same voltage, and the current splits. A break in one branch does not affect the others. That is why appliances at home are wired in parallel — switching one off does not cut the rest.

Why you need this for the exam:

computing the equivalent resistance and the distribution of currents/voltages in both circuit types is a standard problem. Trick: in series add the resistances, in parallel add their reciprocals.

Remember: in series the resistances add (a break puts out everything), in parallel their reciprocals add (the branches are independent).

Illustrative model · NexTutor Virtual laboratory

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Theory & formulas

Series connection

The resistances add up: Rz=R1+R2R_z = R_1 + R_2 A single shared current flows; a break in one element puts out the whole circuit.

Parallel connection

The reciprocals add up (the equivalent resistance is smaller than the smallest one): 1Rz=1R1+1R2\dfrac{1}{R_z} = \dfrac{1}{R_1} + \dfrac{1}{R_2} Each branch has an independent path — unscrewing one bulb does not put out the other.

Notation: RzR_z — equivalent resistance, R1,R2R_1,R_2 — component resistances.

Frequently asked questions

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How do you compute the equivalent resistance for a series connection?

The resistances add up: R_z = R₁ + R₂.

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How do you compute the equivalent resistance for a parallel connection?

From reciprocals: 1/R_z = 1/R₁ + 1/R₂ — the equivalent resistance is smaller than the smallest of the resistors.

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Why does unscrewing one bulb in a parallel circuit not put out the other?

Because each branch has its own independent path for the current; a break in one does not interrupt the others.

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