Virtual laboratory/Physics/Mechanics/Conservation of energy — potential and kinetic energy

Conservation of energy — potential and kinetic energy

What we will do: We will release a cart on a track with hills and check how high it gets and how energy converts between potential and kinetic.

What you see on screen: A roller coaster with a cart, a slider for the start height (and mass), and a friction switch. Two bars — potential and kinetic energy — always add up to the same value (without friction); with friction a "heat" bar appears. Readouts: height, speed, Ep, Ek and total energy.

Conservation of energy — potential and kinetic energy
Physics · Mechanics · Conservation of energy (FIZ.MECH.PP.10)
Start height hh12 m
Cart mass mm1.0 kg
Will the cart make it over the second hill, which is higher than the starting point? (no friction)
height h
12.0 m
speed v
0.0 m/s
Ep = mgh
120 J
Ek = ½mv²
0 J
total E
120 J
🎯 Challenge: from what height should you release the cart so it reaches the target speed in the valley?

What just happened?

The cart did not climb a hill higher than the start — because it had no energy source to do so. Without friction it reaches at most the height it started from.

Two forms of energy:

at the top the cart has potential energy Ep=m g hE_p = m\,g\,h, at the bottom — kinetic Ek=12mv2E_k = \tfrac{1}{2}m v^2. Rolling down, it converts one into the other.

Conservation of mechanical energy (no friction):

Ep+Ek=constE_p + E_k = \text{const}

The sum does not change — energy just "pours" between potential and kinetic. Hence the speed at the bottom:

v=2ghv = \sqrt{2 g h}

And friction?

Then part of the mechanical energy turns into heat, so the cart returns lower each time — yet the total energy is still conserved, only part of it "escapes" as heat.

Why you need this for the exam:

Ep = mgh, Ek = ½mv² and their sum solve problems about falling, rolling down and speed without computing forces. The trick: equate the energy at two points of the track.

Remember: energy is not lost — it changes form. Without friction you cannot get higher than the starting point. This is the third in the family of conservation laws: mass, momentum, energy.

Illustrative model · NexTutor Virtual laboratory

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Theory & formulas

Two forms of mechanical energy

  • potential (gravitational): Ep=mghE_p = m g h
  • kinetic: Ek=12mv2E_k = \tfrac{1}{2}m v^2

The law of conservation of mechanical energy

Without friction the sum of potential and kinetic energy is constant: Ep+Ek=constE_p + E_k = \text{const} At the top of a hill the energy is mostly potential, at the bottom — kinetic.

Speed from height

From the conversion of EpE_p into EkE_k (mgh=12mv2mgh = \tfrac{1}{2}mv^2): v=2ghv = \sqrt{2 g h} With friction part of the mechanical energy turns into heat, but the total energy is still conserved.

Notation: EpE_p — potential energy, EkE_k — kinetic energy, mm — mass, g≈9.81 m/s2g \approx 9.81\ \mathrm{m/s^2}, hh — height, vv — speed.

Frequently asked questions

›

What does the law of conservation of mechanical energy state?

Without friction the sum of potential and kinetic energy is constant: Ep + Ek = const.

›

How do you calculate the speed of a body falling from height h?

From the conservation of energy: v = √(2gh).

›

Where does the energy go when there is friction?

It turns into heat — the total energy is still conserved, but the mechanical energy decreases.

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