Virtual laboratory/Physics/Oscillations/Energy in oscillatory motion — Ep and Ek

Energy in oscillatory motion — Ep and Ek

Drag the mass on the spring. At the extreme displacement all the energy is potential (½kx²); at the equilibrium position — all of it is kinetic. The sum stays constant (½kA²). Watch how the Ep and Ek bars pour into each other.

Energy in oscillatory motion — Ep and Ek
Physics · Oscillations · Energy in simple harmonic motion (FIZ.DRG.PP.02)
Displacement xx (from −A-A to +A+A)6.0 cm
At the equilibrium position (x = 0) the oscillation energy is:
displacement x
6.0 cm
energy Ep
0.36 J
energy Ek
0.64 J
total E
1.00 J
🎯 Challenge: split the energy
streak: 0

I will give you a target potential energy — set the displacement x to reach it. Ep = ½kx², and E = 1.0 J.

What just happened?

A mass on a spring stores energy in two ways: when it is displaced, the energy sits in the stretched spring (potential); when it races through the middle, it sits in the motion (kinetic). The sum is always the same.

Oscillation energy balance:

Ep=12kx2Ek=E−EpE_p = \tfrac{1}{2}kx^2 \qquad E_k = E - E_p

— potential energy grows with the square of displacement, and kinetic is the rest up to the constant total. k — spring constant (N/m), x — displacement (m), A — amplitude.

Invariant — what stays constant?

E=Ep+Ek=12kA2=constE = E_p + E_k = \tfrac{1}{2}kA^2 = \text{const}

At the extreme position (x=±Ax = \pm A) the speed is zero, so E=EpE = E_p — all the energy is potential. At equilibrium (x=0x = 0) the spring is slack, so E=EkE = E_k — all of it is kinetic. Between them the energy just "sloshes" from one form to the other.

Why you need this for the exam:

Conservation of mechanical energy solves most oscillation problems — without computing forces and accelerations. Trick: at the extreme point compute from E=12kA2E = \tfrac{1}{2}kA^2, and find the maximum speed from 12mvmax2=12kA2\tfrac{1}{2}mv_{max}^2 = \tfrac{1}{2}kA^2.

Remember: in oscillations the energy circulates between Ep and Ek, but their sum E = ½kA² is constant. Extreme = pure potential, middle = pure kinetic.

Illustrative model · NexTutor Virtual laboratory

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Theory & formulas

Energy exchange

In oscillatory motion the potential and kinetic energy convert into each other:

  • extreme displacement: all energy potential Ep=12kx2E_p=\tfrac12 kx^2 (max), Ek=0E_k=0
  • equilibrium position: all kinetic EkE_k (max), Ep=0E_p=0

Total energy

The sum is constant (undamped oscillations): E=12kA2=constE = \tfrac12 k A^2 = \text{const} It depends on the square of the amplitude — 2× larger amplitude means 4× larger energy.

Symbols: EpE_p — potential energy, EkE_k — kinetic, kk — spring constant, xx — displacement, AA — amplitude, EE — total energy.

Frequently asked questions

›

Where is the oscillation energy purely kinetic?

At the equilibrium position (x=0), where the displacement is zero and the speed is maximal; Ep=0, so all the energy is Ek.

›

What does the total oscillation energy depend on?

On the square of the amplitude: E=½kA²; twice the amplitude means four times the energy.

›

Is the oscillation energy conserved?

In undamped oscillations, yes — Ep and Ek change, but their sum stays constant.

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